/**
   This program demonstrates how the Integer.parseInt
   method throws an exception.
*/
import java.io.*;  
import javax.swing.JOptionPane; 


public class eg45_ParseIntError
{
   public static void main(String[] args)
   {
       //String str = "abcde";
       int number;
	   String input;
	   boolean valid = false;
	
		while (!valid)
		{
		
		try
		{
			input = JOptionPane.showInputDialog("Enter a integer >=0:");
			number = Integer.parseInt(input);
			if (number >=0)
				valid = true;
			
		}
		catch (NumberFormatException e)
		{ 
			System.out.println("Conversion error: " + e.getMessage());
		}
		
		}
   }
}